The ages of four cousins are consecutive integers. Let the integers equal n, n+1, n+2, n+3. The sum of their ages is 26. How old is each cousin?

The answers would be n=5 n+1=6 n+2=7 n+3=8 because the equation is 4n+6=26. You add all the variables and numbers up to get that equation. Then you subtract 6 from 26 to get 20. Finally you divide 20 by 4 to get n=5. To get all the ages you replace n with 5 and complete the equation. For example n+1 is actually 5+1.

31 is prime. and it’s prime factorization is just 31.

How am i goonna know explain