E Question Help Challenge The price of Stock A at 9 AM was $16.09. Since then, the price has been increasing at
the rate of $0.12 each hour. At noon the price of Stock B was $16.84. It begins to decrease at the
rate of $0.15 each hour. If the two rates continue, in how many hours will the prices of the two
stocks be the same?

in about ___ hours the prices of the two stocks will be the same?

If only it were that easy.  After 1.44 hours, the price of the two stocks will be the same, 16.62.

Step-by-step explanation:

Let t be the time (in hours) after noon.

Stock(A) = 16.09 + 0.12 (t +3)

Stock(B) = 16.84 - 0.15t

Stock(A) = Stock(B)

16.09 + 0.12 (t+3) = 16.84 - 0.15t

16.09 + 0.12t + 0.36 = 16.84 - 0.15t

0.27t = 0.39

t=1.44 hours

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;

a_n = a_1 + (n - 1)d

the first term is 6.

the common difference d = ?

when you find d, replace n with 7 and d with the common difference to find your answer.