Mathematics, 03.11.2020 06:10 ChaosMind

Determine the measures of ZACB, ZDCE, & ZBCD.

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Answer from: Quest

there are lots of ways. pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula. the area is half the sum of the cross products of the sides.

a(-2,6) -2(2)-6(-5) = 26

b(-5,2) -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3) 4(3) - (-3)(5) = 27

e(5,3) 5(3) - 3(1) = 12

f(1,3) 1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 + 18 + 27 + 12 + 12) = 57

that checks!

Find the area of the following shape. you must show all work to receive credit. need asap timed tes

Answer from: Quest

so, converting firstly the mixed fractions to improper fractions and then "adding".

$\bf \stackrel{mixed}{2\frac{9}{10}}\implies \cfrac{2\cdot 10+9}{10}\implies \stackrel{improper}{\cfrac{29}{10}}~\hfill \stackrel{mixed}{5\frac{4}{15}}\implies \cfrac{5\cdot 15+4}{15}\implies \stackrel{improper}{\cfrac{79}{15}} [-0.35em] ~\dotfill$

$\bf -\cfrac{29}{10}+\left( -\cfrac{79}{15} \right)\implies -\cfrac{29}{10}-\cfrac{79}{15}\implies \stackrel{\textit{using the lcd of 30}}{\cfrac{-(3)29-(2)79}{30}}\implies \cfrac{-87-158}{30} \cfrac{-245}{30}\implies -\cfrac{49}{6}\implies -8\frac{1}{6}$

Answer from: Quest

$x=-2$ or $x=-5$

step-by-step explanation:

we need to solve for 'x' the following equation: $\sqrt{(x+6)} - 4 = x$

we have that:

$\sqrt{(x+6)} - 4 = x$ ⇒ $(x+6) = (x+4)^{2}$

⇒ $x+6 = x^{2} + 8x + 16$ ⇒ $x^{2} + 7x + 10 = 0$

factorizing, we get that:

$x^{2} + 7x + 10 = 0$ ⇒ $(x+2)(x+5)=0$

then, the solutions are: $x=-2$ or $x=-5$

nothing extraneous has been found!

Answer from: Quest

1. sometimes

2. never

3 .08c = 7.50+.05c 250 pages

step-by-step explanation:

1. sometimes

the theoretical probability of rolling a 1 is 1/6. perhaps you got really lucky and never rolled a 1 in those 60 times. your experimental probability is 0. or perhaps you rolled a 1 20 times. your experimental probability is 20/60 is 1/3. it really just depends on how you rolled in that experiment.

2. never

the probability of the event occurring is 1. that is being 100 % sure it will happen. that is the maximum amount of confidence we have.

3. no customer card cost: .08 times number of pages

customer card cost: 7.50 + .05 times number of pages

we want to find when it costs the same amount, so we will set these equal

let c = number of pages

.08c = 7.50+.05c

subtract .05c from each side

.08c-.05c = 7.5+.05c-.05c

.03c=7.5

divide each side by .03

.03c/.03 = 7.5/03

c =250

the cost is the same at 250 pages

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Determine the measures of ZACB, ZDCE, & ZBCD.
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