The length of the diagonal of a rectangle is 11 cm more than the width and the width is 3 cm less than the length. If the area is 990 cm^2, find the length of the rectangle.

33cm

Step-by-step explanation:

area of a rectangle= length ×width

Let x be the length

990=x( x-3)

990=x^2-3x

x^2-3x-990=0

x^2+30x-33x-990=0

x(x+30)-33(x+30)=0

(x-33)(x+30)=0

x=33, x=-30

length is positive so it'll be 33cm

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.

a28=58

step-by-step explanation:

a1=a1+(n-1)d

a28= 4+ (28-1)2

a28=4+(27)(2)

a28=4+54

a28=58