Polynomial Practice. Can y’all help? And not just type in random letters to get points. Given f(x)=x^3-28x-48 has x=-4 as a zero, find the other zeros.

I’m guessing solving through Synthetic Division and Long Division.

answer: i don't understand it

step-by-step explanation: sorry

about 0.75 hours

step-by-step explanation:

hi how are you doing today, if you need just ask me.

step-by-step explanation:

answer:

given the linear inequality :

add 2y to both sides we get;

simplify:

add 12 to both sides of an equation;

simplify:

divide both sides by 2 we get;

or

the related equation for the inequality equation [1] is;

y-intercepts defined as the graph crosses the y-axis.

substitute x =0 in [2] to solve for y;

y = 6

x-intercepts defined as the graph crosses the x-axis.

substitute value y = 0 to solve for x;

subtract 6 from both sides we get

multiply both sides by 2 we get;

or

x = -12

now, plot these point (0, 6) and (-12, 0) on graph as shown below and shade the graph below the solid line.