Please help now!! Given triangle ACP and triangle LNX, find each missing measure.

Answer/Step-by-step explanation:

Given:

m<A = 29°

PA = 13 cm

LN = 21 cm

Since ∆ACP ≅ ∆LNX (isosceles ∆s), therefore,

<A = <L

<C = <N

<P = <X

AC = LN

XL = PA

XN = PC

since, XL = XN (equal sides of isosceles ∆LNX), therefore, PA = PC

Thus,

Since XL = PA

XL = 13 cm (substitution)

Since AC = LN

AC = 21 cm (substitution)

Since PC = PA,

PC = 13 cm (substitution)

Since <L = <A,

m<L = 29° (substitution)

Since ∆ACP is an isosceles ∆, the base angles are equal. Therefore,

m<C = m<A

m<C = 29° (substitution)

m<X = m<P

m<P = 180 - (29 + 29) (sum of ∆ACP)

m<P = 122°

Therefore,

m<X = 122° (corresponding angles of congruent ∆s)

no

step-by-step explanation:

2-7=-5

7-2=5

when you combing like terms for ech expression, 5 and -5. these numbers are not equal to each other.