Ming has 15 quarters, 30 dimes, and 48 nickels. he wants to group his money so that each group had the same number of each coin. what is the greatest number of groups he can make? how many of each coin will be in each group? how much money will each group be worth?

Find the greatest common factor. In this case it is 3. Divide each group by 3.
15÷3=5 quarters
30÷3=10 dimes
48÷3=16 nickels
Next count them by the coin's value:
5 × 0.25 = $1.25
10 × 0.10 = $1
16 × 0.05 = $0.80
Add them up:
= $3.05 in each group and there are three groups.

So, the greatest number of groups that he can make is 3; there will be 5 quarters, 10 dimes, and 16 nickels in each group, which is worth $3.05 in each group.

Ac equals 35 cm long