PLEASR HELP I'LL GIVE YOU BRAINIEST:)) The function y= 0.75x+2 represents the cost y ( in dollars ) of an ice cream sundae with x toppings. A sundae comes with 1,2,3, or 4 toppings. Identify the Independent and dependent variables, the domain and the range.

Options: 1) y , 2) 2.75,3.50,4.25, & 5 , 3) x , 4) 1,2,3, and 4

Independent variable: no. of toppings, x

Dependent variable: cost of ice cream, y.

Domain: {1, 2, 3, 4}

Range: {2.75, 3.50, 4.25, 5.00}

Step-by-step explanation:

The independent variable is the toppings, x, while the dependent variable is the cost of the ice cream, y.

The domain are the set of possible values of x, which include {1, 2, 3, 4, 5}

The range is the set of all y-values corresponding to the x-values.

Plug in each domain value into the equation given, y= 0.75x+2, to solve for each corresponding y-values.

When x = 1,

y = 0.75x + 2

y = 0.75(1) + 2 = 0.75 + 2

y = 2.75

When x = 2,

y = 0.75x + 2

y = 0.75(2) + 2 = 1.50 + 2

y = 3.50

When x = 3,

y = 0.75x + 2

y = 0.75(3) + 2 = 2.25 + 2

y = 4.25

When x = 4,

y = 0.75x + 2

y = 0.75(4) + 2 = 3 + 2

y = 5.00

Therefore, the range includes {2.75, 3.50, 4.25, 5.00}

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)