Sue had 48 ribbons at first. Her mother gave her 65 ribbons, and kim gave her 89. Now sue has 62 more ribbons than her mother and 35 fewer than kim. How many ribbons did sue's mother and kim have at first. Use bar models to show your work

Her mother had 205 ribbons at first

Kim had 256 ribbons at first.

Step-by-step explanation:

Sue had 48 ribbons at first. Her mother gave her 65 ribbons,and kim gave her 89.

The total ribbons that sue has is:

48 + 65 + 89

= 202

Let the number of ribbons her mother has = m

The number of ribbons her sister had = k

Now sue has 62 more ribbons than her mother

Therefore presently,

202 = 62 + m

m = 202 - 62

m = 140 ribbons

Her mother has 140 ribbons presently

35 fewer than kim.

k = 202 - 35

k = 167

Kim has 167 ribbons presently

How many ribbons did sue's mother and kim have at first

We are told in the question that:

Her mother gave her 65 ribbons

Hence, her mother had

140 + 65

= 205 ribbons at first

Her mother had 205 ribbons at first

Kim gave her 89.

Hence ,

89 + 167

= 256 ribbons at first

Kim had 256 ribbons at first.

its electric no smoke

step-by-step explanation:

d

step-by-step explanation:

given

y + 3 = - 4(x - 2) ← distribute the parenthesis

y + 3 = - 4x + 8 ( subtract 3 from both sides )

y = - 4x + 5 → d