The number of students using the ATM on campus daily is normally distributed with a mean of 240 and a standard deviation of 50. Based upon a random sample of 100 days, what is the probability that the ATM usage averaged more than 247 students per day

The probability is 0.080757

Step-by-step explanation:

We start by calculating the z-score

z-score = (x-mean)/SD/ √n

In this case;

x = 247 , mean = 240, SD = 50 and n = 100

z-score = (247-240)/50/√100

z-score = 7/50/10

= 7/5 = 1.4

So the probability we want to calculate is;

P( x > 1.4)

we can use the standard normal distribution table for this

P(x > 1.4) = 0.080757

7/2

(decimal: 3.5)

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