Can any kind soul help me

x(x-2) = 5

=> x^2 -2x-5 = 0

a=1, b= -2, c= -5

Discriminant= b^2-4ac

= (-2)^2 - 4(1)(-5)

=4+20

=24

Since Discriminant > 0

Therefore the roots are real and distinct.

Hope it helps mark me as brainliest

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions