In the expression 3(2^0), what is the order of operations? Explain how would you evaluated the expression.

We'll use PEMDAS which stands for

P = parenthesis

E = exponents

M = multiplication

D = division

A = addition

S = subtraction

It tells us the order in how to evaluate math expressions. We start with parenthesis, then move to exponents, etc until we get to subtraction as the last step.

We have parenthesis so we focus on whats inside it. We evaluate 2^0 to get 1. Any nonzero number to the exponent 0 is always 1. In other words, x^0 = 1 where x is nonzero.

So 3(2^0) turns into 3(1) or 3*1

Then we multiply that to get 3*1 = 3

So overall, 3(2^0) = 3

6 on both sides and twelve on the top and the bottom

step-by-step explanation: