Prove that 1-tan32°tan13°-tan32°-tan13°=0

Step-by-step explanation:

45=32+13

tan 45=tan(32+13)

or  1-tan 32 tan 13-tan 32-tan 13=0

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

(a) the volume of the cone is 20/3 in3

hence, option a is correct.