![\lim_{x \to \ 4}[\frac{sin \pi x }{x^2-16} ]](/tpl/images/0858/2915/e2154.png)
![\lim_{x \to \ 4}[\frac{\pi cos \pi x }{2x} ]](/tpl/images/0858/2915/db3d7.png)
![\lim_{x \to \ 4}[\frac{\pi cos 4\pi }{8} ]](/tpl/images/0858/2915/b6a1d.png)
![4[\frac{1}{8}]](/tpl/images/0858/2915/247b5.png)
Find the limits using L'Hospital's rule is possible:
lim (sin pix)/(x^2-16)
x->...
Mathematics, 31.10.2020 17:50 ayoismeisjjjjuan
Find the limits using L'Hospital's rule is possible:
lim (sin pix)/(x^2-16)
x->4
Answers: 1
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