Unit 4 Homework 2 Gina Wilson all things algebra,
Pls help!

1. m∠1 = 45°

2. m∠1 = 129°

3. m∠1 = 37°

4. m∠1 = 88°

m∠2 = 42°

m∠3 = 113°

5. m∠1 = 62°

m∠2 = 45°

m∠3 = 24°

6. m∠1 = 128°

m∠2 = 52°

m∠3 = 47°

m∠4 = 133°

7. m∠1 = 41°

m∠2 = 85°

m∠3 = 95°

m∠4 = 85°

m∠5 = 36°

m∠6 = 50°

m∠7 = 107°

8. x = 9°

10. x = 5°

11. x = 7°

Step-by-step explanation:

1. m∠1 = 180° - (76° + 59°)  = 45°

m∠1 = 45°

2. m∠1 = 62° + 67°  = 129°

m∠1 = 129°

3. m∠1 = 152° - 115° = 37°

m∠1  = 37°

4. m∠2 = 42° (Alternate angles)

m∠1 = 180° - (50° + m∠2) = 180° - (50° + 42°) = 88°

m∠1 = 88°

m∠3 = 180° - (25° + 42°) = 113°

m∠3 = 113°

5. m∠3 = 73° - 49° = 24°

m∠3 = 24°

m∠2 = 118° - 73° = 45°

m∠2 = 45°

m∠1 = 180° - (73° + 45°) = 62°

m∠1 = 62°

6. m∠2 = 52° (Alternate interior angles)

m∠1 = 180° - 52° = 128° (The sum of angles on a straight line)

m∠1 = 128°

m∠3 = 47° (Alternate interior angles)

m∠4 = 180° - 47° = 133° (The sum of angles on a straight line)

m∠4 = 133°

7. m∠3 = 95° (Vertically opposite angles)

m∠2 = m∠4  (Vertically opposite angles)

m∠3 + 95° + m∠2 + m∠4 = 360° (The sum of angles at a point)

2 × 95° + 2 × m∠2 = 360°

m∠2 = (360° - 2 × 95°)/2 = 85°

m∠2 = 85° = m∠4

m∠2 = 85°

m∠4 = 85°

m∠1 = 360° - (85° + 140° + 90°) = 41°

m∠1 = 41°

m∠5 = 180° - 144° = 36°

m∠5 = 36°

m∠6 = 180° - (m∠5 + m∠3) = 180° - (36 + 95°) = 50°

m∠6 = 50°

m∠7 = 360° - (m∠4 - 38° - (180° - m∠6)) = 360° - (85° - 38° - (180° - 50°)) = 107°

m∠7 = 107° (Sum of angles in a quadrilateral)

8. (10·x - 11)° + (3·x - 2)° + (3·x + 1)° = 180°

Using an online application, we have;

(6·x - 12)° = 180°

x = (180 + 12)°/6 = 32°

x = 32°

9. (3·x - 5)° + (7·x + 5)° + 90° = 180°

Using an online application, we have;

10·x = 180° - 90° = 90°

x = 90°/10 = 9°

x = 9°

10. 151° = (11·x - 1)° + (20·x - 3)°

151° = 31·x - 4°

31·x = 151° + 4° = 155°

x = 155°/31 = 5°

x = 5°

11. (14·x - 13)° = (4·x + 13)° + (6·x + 2)°

(14·x - 13)° = (10·x + 15)°

(14·x - 10·x)° = (13 + 15)° = 28°

4·x = 28°

x = 28°/4 = 7°

x = 7°

i dont know

step-by-step explanation:

"standard form:

3x2 + 14x − 10 = 0

solutions based on quadratic formula:

x1   = −14 − √ 142 − 4×3×(−10) /   2×3   = −14 − 2 × √ 79 /   6   ≈ −5.296

x2   = −14 + √ 142 − 4×3×(−10) /   2×3   = −14 + 2 × √ 79 /   6   ≈ 0.629