What is an equation of the line that passes through the point (-3,-7)(−3,−7) and is parallel to the line 3x-y=53x−y=5?

y  = -3x-14

Step-by-step explanation:

Any line parallel to  

y

=

−

3

x

+

6

will be in the form  

y

=

−

3

x

+

c

for some constant  

c

If  

(

x

,

y

)

=

(

−

3

,

−

5

)

is a solution to such an equation, then replacing  

y

with  

(

−

5

)

and  

x

with  

(

−

3

)

gives

−

5

=

(

−

3

)

⋅

(

−

3

)

+

c

→

−

5

=

9

+

c

→

c

=

−

14

So the desired parallel line would have the equation

y

=

−

3

x

−

14

y=mx+b

step-by-step explanation:

m slope

b y-intercept

for this pair of functions g(x)=x-2 and f(x)=|x| is (g o f)(a)= |a| -2

step-by-step explanation:

g(x)=x-2

f(x)=|x|

(g o f)(a)=?

(g o f)(x)=g(f(x))

(g o f)(x)=g(|x|)

(g o f)(x)=|x|-2

(g o f)(a)=|a|-2