Linear Algebra, show steps please.

If x is in the nullspace of A, then Ax = 0. Consider the augmented matrix

Add row 2 to row 1 to get this into reduced-row echelon form:

Then x = [x₁, x₂, x₃]ᵀ such that

x₁ - x₃ = 0

x₂ - 3 x₃ = 0

If you let x₃ = 1, you end up with x₁ = 1 and x₂ = 3, so x = [1, 3, 1]ᵀ.

More generally, if you let x₃ = y, then any vector of the form [y, 3y, y]ᵀ would belong to the nullspace.

Check that this is orthogonal to the rows of A :

[1, -1, 2] • [1, 3, 1]ᵀ = 1•1 + (-1)•3 + 2•1 = 1 - 3 + 2 = 0

[0, 1, -3] • [1, 3, 1]ᵀ = 0•1 + 1•3 + (-3)•1 = 0 + 3 - 3 = 0

3/6   and 9/18

step-by-step explanation:

a - base

b - exponent

so,