-2(y-5) + 10 = 6y + 20 how many solutions does the equation have? one solution, No solution, infinite solutions or cannot determine? help me out please

No solution

Step-by-step explanation:

Step 1: Simplify both sides of the equation.

−2(y−5)+10=6y+20

(−2)(y)+(−2)(−5)+10=6y+20(Distribute)

−2y+10+10=6y+20

(−2y)+(10+10)=6y+20(Combine Like Terms)

−2y+20=6y+20

−2y+20=6y+20

Step 2: Subtract 6y from both sides.

−2y+20−6y=6y+20−6y

−8y+20=20

Step 3: Subtract 20 from both sides.

−8y+20−20=20−20

−8y=0

Step 4: Divide both sides by -8.

−8y

−8

=

0

−8

y=0

first, you divide the triangle in two, tô form a retangle triangle. after, using pythagoream theorem:

18^2 = 14^2 + (x/2)^2

(x^2/4) + 196 = 324

x^2/4 = 324 - 196

x^2/4 = 128

x^2 = 512

x = √512

x = √2^9

x = 16√2 cm

i hope i you.