12 women and 18 men are on the faculty in the Computer Science department at Whatsamatta U. a. How many ways are there to select a committee of 6 members of the department if at least two women must be on the committee

183,600 ways

Step-by-step explanation:

TOPIC : PERMUTATION & COMBINATION

Question: In how many ways can a committee of 6 members - with at least 2 women - be selected?

In other words, how many ways are there, to select a committee of 6 members including at least 2 women?

* Permutation deals with the orderly arrangement of items while Combination deals with the manner of selection of items from a group, without regard to order. In other words, this question has to do with Combination.

There are 12 women and 18 men and you're to select 2 women and 4 men.

The combination for men and women will be found separately and then multiplied together.

WOMEN: 2 OUT OF 12

12! ÷ [2! × (12 - 2)!]  =  12! ÷ [2! 10!]

= 12×11×10×9×8×7×6×5×4×3×2×1   = 479,001,600  =  66

  2×1   ×10×9×8×7×6×5×4×3×2×1       7,257,600

MEN: 4 OUT OF 18

18! ÷ [4! (18 - 4)!]  =  18! ÷ [4! 14!]

= 18×17×16×15×14×13×12×11×10×9×8×7×6×5×4×3×2×1  = 3,060

  4×3×2×1   ×14×13×12×11×10×9×8×7×6×5×4×3×2×1

₁₂C₂  ×  ₁₈C₄  = 66 × 3060  = 183,600

81 seats

step-by-step explanation:

if you multiply 0.65 times 125 then you get 81.5 seats. well since you can't have half of a seat you have to round down and get 81 seats in the no children zones. that leave 44 seats outside of the no children zone.