A decision maker is interested in estimating a population proportion. A sample of size n150 yields 115 successes. Based on these sample data, construct a 90% confidence interval estimate for the true population proportion. A. (0.714, 0.826) B. (0.717, 0.823) C. (0.750, 0.790) D. (0.737, 0.803)

A. (0.714, 0.826)

Step-by-step explanation:

Given that:

The sample size n = 150

The number of success(sample proportion) x = 115

The population proportion =  

The population proportion =

The population proportion = 0.767

At 90% confidence interval level;

Thus, the confidence interval estimate for the true population proportion can be computed by using the formula:

= (0.767 - 0.0568,  0.767 + 0.0568)

= (0.7102 , 0.8238 )

Due to approximation;  the confidence interval estimate for the true population proportion  is  (0.714, 0.826)

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