A particular fruit's weights are normally distributed, with a mean of 720 grams and a standard deviation of 38 grams. The heaviest 19% of fruits weigh more than how many grams? Give your answer to the nearest gram.

The heaviest 19% of fruits weigh more than 753grams.

Step-by-step explanation:

Let X = fruit's weights that are normally distributed.

Given:

To find : x such that P(X>x)=19%

i.e. P(X<x) = 81%  [100%-19%=81%]

i.e. P(X<x) = 0.81

Since, and from z-table the z value for p-value of 0.81 (one -tailed) = 0.8779

Hence, the heaviest 19% of fruits weigh more than 753grams.

answer:

the position of equilibrium will shift to the left.

step-by-step explanation:

the general equation for the dissociation of a weak base is

b + h₂o   ⇌   bh⁺ + oh⁻

according to le châtelier's principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

if you apply a stress by adding more bh⁺ or oh⁻,   the system will respond by moving in a direction that gets rid of the added ions.

the position of equilibrium will shift to the left, forming more of the undissociated base.