Anthony has 260 cars and sells them at a rate of 5 cards a day. Ben has 100 cards and buys them at a rate of 3 cards per day. After how many days will they have the same number of cards

After 20 days, they will have the same number of cards

Step-by-step explanation:

Given;

number of cards with Anthony, = 260 cards

rate of his sale = 5 cards/day

number of cards with Ben, = 100 cards

rate of his purchase, = 3 cards/day

let the number of days when they will have the same number of card = n

set up the linear equation, consider sale as subtraction from the initial value and also consider purchase as an addition to the initial value.

260 - 5n = 100 + 3n

260 -100 = 3n + 5n

160 = 8n

n = 160 / 8

n = 20 days

Therefore, after 20 days, they will have the same number of cards

75 tickets have been sold so far.

step-by-step explanation:

in this question it is clearly mentioned that 45 children's tickets have been sold and this number is 60% of the total tickets sold.

now let's assume the total number of tickets sold be x.

then 60% of x = 45

⇒

⇒ x(.6) = 45

by dividing with .6 on both the sides of the equation

⇒ x = 75

therefore 75 tickets have been sold so far.