The proportion of brown M&M’s in a milk chocolate packet is approximately 14% (Madison, 2013). Suppose a package of M&M’s typically contains 52 M&M’s. a.) State the random variable. b.) Find the mean. c.) Find the variance. d.) Find the standard deviation.

a) Let x be a random variable that represents the number of brown M&M’s in a milk chocolate packet.

b) Mean =7.28

c) Variance = 6.2608

d) Standard deviation = 2.5022

Step-by-step explanation:

Given : The proportion of brown M&M’s in a milk chocolate packet is approximately : p=14% =0.14

We have outcomes for every randomly selection : 1) its in a milk chocolate packet 2) its not.

a) Let x be a random variable that represents the number of brown M&M’s in a milk chocolate packet.

So x follows binomial distribution.

b) Sample size : n=52  (given)

Mean

c) Variance =

d) Standard deviation =

dalila is incorrect. the whisker on the left is very long, going all the way out to 5. the whisker goes from 5 to 30, so it has a spread of 25. the rest of the box plot values are closer together, so 5 is an outlier

60°

step-by-step explanation:

the measure angle of c in an isosceles triangle abc is 60° because in isosceles triangle,the measures of all the angles is 60°.