An object is launched at 20 m/s from a height of 65 m. The equation for the height (h) in terms of time (t) is given by h(t) = -4.912 + 20t + 65. What is the object's maximum height?

The maximum height is the y-value of the vertex.

h(t) = -4.9t² + 20t + 65

     a=-4.9   b=20  c=65

h(2) = -4.9(2)² + 20(2) + 65

     = -19.6 + 40 + 65

     = 85.4

Step-by-step explanation:

may i see the picture? it would a lot, xox

12

step-by-step explanation:

a triangle's   full angle is 180 degrees so 180 - 156 = 24. 24/2=12