In ΔJKL, \overline{JL} JL
is extended through point L to point M, \text{m}\angle KLM = (7x+3)^{\circ}m∠KLM=(7x+3)
∘
, \text{m}\angle LJK = (2x+12)^{\circ}m∠LJK=(2x+12)
∘
, and \text{m}\angle JKL = (3x+7)^{\circ}m∠JKL=(3x+7)
∘
. Find \text{m}\angle LJK. m∠LJK.

Answer: d. 39 cmin the diagram, the approximate length of the minor arc de is 39 centimetres.step-by-step explanation: the formula for the length of an arc in a circle is as displayed below.let the length of the minor arc de = xx = 2( pi )r × angle of sector / 360°from this, we will substitute the values given from the problem into the formula to obtain the length of the minor arc de.x = 2( pi )r × angle of sector / 360°r = radius = 25cmpi as an approximate value = 3.14angle of sector = 120°x = 2( 3.14 )( 25 ) × 120° / 360°x = 157 × 1 / 4x = 39.25x = 39 ( rounded to the nearest whole number as an approximate value )