chose the point slope from the equation below that represents the line that passes through the points (-3, 2) and (2, 1)

Step-by-step explanation:s

l

o

p

e

=

y

2

−

y

1

x

2

−

x

1

y

=

−

1

5

x

+

7

5

Explanation:

The slope of the line passing through the two points

(

−

3

,

2

)

and

(

2

,

1

)

is given by

s

l

o

p

e

=

y

2

−

y

1

x

2

−

x

1

s

l

o

p

e

=

1

−

2

2

−

(

−

3

)

s

l

o

p

e

=

−

1

5

The equation of the straight line is

y

=

a

⋅

x

+

b

s

l

o

p

e

=

a

=

−

1

5

y

=

−

1

5

x

+

b

The point

(

2

,

1

)

is a point on the straight line. Plugging the coordinates of this point and the line equation allows us to find the Y-intercept.

1

=

−

1

5

×

2

+

b

b

=

1

+

2

5

b

=

7

5

The equation of the straight-line will be

y

=

−

1

5

x

+

7

5

To find the X-intercept assign the value 0 to

y

0

=

−

1

5

x

+

7

5

1

5

x

=

7

5

x

=

7

graph{-1/5*x+7/5 [-9.63, 10.37, -3.4, 6.6]}

y -5 = (-1/4)(x + 8)

step-by-step explanation: