The sum of two consecutive odd integers is 20 less than four times the smaller of the two integers. Which of the following equations could be used to find the smaller integer, n?
(1)(n+1)+(n+3) = 20 - 4n
(2) n+ (n + 2) = 4n-20
(3) (n+3)+n=20-4n
(4) n+(n+ 2) = 4(n-20)

step-by-step explanation:

(a) {a₁, a₁r, a₁r², … a₁rⁿ⁻¹, …}

(b) $59 398

step-by-step explanation:

(a) the annual sequence of profits

aₙ = a₁rⁿ⁻¹

the model for the sequence of profits is {a₁, a₁r, a₁r², … a₁rⁿ⁻¹, …} .

(b) profit after 15 yr

  a₁ = $ 30 000

  r = 1.05

a₁₅ = 30 000 × 1.05¹⁴

a₁₅ = 30 000 × 1.979 93

a₁₅ = $59 398

the profit in year 15 will be $59 398.

33/100 is what i got