−3 1/3⋅(−2 7/10) Please Help Me

9

Step-by-step explanation:

Simplify the following:

-(3 + 1/3) (-(2 + 7/10))

Hint: | Multiply all instances of -1 in -(3 + 1/3) (-(2 + 7/10)).

(-1)^2 = 1:

(3 + 1/3) (2 + 7/10)

Hint: | Put the fractions in 2 + 7/10 over a common denominator.

Put 2 + 7/10 over the common denominator 10. 2 + 7/10 = (10×2)/10 + 7/10:

(3 + 1/3) (10×2)/10 + 7/10

Hint: | Multiply 10 and 2 together.

10×2 = 20:

(3 + 1/3) (20/10 + 7/10)

Hint: | Add the fractions over a common denominator to a single fraction.

20/10 + 7/10 = (20 + 7)/10:

(3 + 1/3) (20 + 7)/10

Hint: | Evaluate 20 + 7.

20 + 7 = 27:

(3 + 1/3)×27/10

Hint: | Put the fractions in 3 + 1/3 over a common denominator.

Put 3 + 1/3 over the common denominator 3. 3 + 1/3 = (3×3)/3 + 1/3:

27/10 (3×3)/3 + 1/3

Hint: | Multiply 3 and 3 together.

3×3 = 9:

((9/3 + 1/3)×27)/10

Hint: | Add the fractions over a common denominator to a single fraction.

9/3 + 1/3 = (9 + 1)/3:

27/10 (9 + 1)/3

Hint: | Evaluate 9 + 1.

9 + 1 = 10:

10/3×27/10

Hint: | Express 10/3×27/10 as a single fraction.

10/3×27/10 = (10×27)/(3×10):

(10×27)/(3×10)

Hint: | Cancel common terms in the numerator and denominator of (10×27)/(3×10).

(10×27)/(3×10) = 10/10×27/3 = 27/3:

27/3

Hint: | Reduce 27/3 to lowest terms. Start by finding the GCD of 27 and 3.

The gcd of 27 and 3 is 3, so 27/3 = (3×9)/(3×1) = 3/3×9 = 9:

9

use the power rule  

( a b ) n = a n b n

to distribute the exponent.

apply the product rule to  

3 x 2 y 3 . ( 3 x 2 ) 2 ( y 3 ) 2

apply the product rule to  

3 x 2 . 3 2 ( x 2 ) 2 ( y 3 ) 2

raise  

3

to the power of  

2 . 9 ( x 2 ) 2 ( y 3 ) 2 multiply the exponents in   ( x 2 ) 2

.

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 2 ⋅ 2 ( y 3 ) 2

multiply  

2   by   2 . 9 x 4 ( y 3 ) 2

multiply the exponents in  

( y 3 ) 2 .

apply the power rule and multiply exponents,  

( a m ) n = a m n . 9 x 4 y 3

⋅

2

multiply  

3   by   2 . 9 x 4 y 6

step-by-step explanation: