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Mathematics, 29.10.2020 01:30 Neon29
The zeros of the function f(x)= -(x+1)(x-3)(x+2) are -1, 3, and __, and the y-intercept of the function is located at (0,__). Fill in the blanks.
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The zeros of the function f(x)= -(x+1)(x-3)(x+2) are -1, 3, and __, and the y-intercept of the funct...
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