Which of the following equations could you solve by first adding six and then dividing by negative three?
3x - 6 = -9
6 - 3x = -9
-3x - 6 = -9
x/-3+ 6 = -9

 -3x - 6 = -9

Step 1. Add 6 to both sides
           -3x - 6 + 6 = -9 + 6
               -3x = -3 
            then dividing by negative three to both sides 
                 -3x/-3 = -3/-3
               x = 1

Iagree that is the answer to the question