Y=x² - 6x + 5
(Find the vertex, show steps )

Y=ax²+bx+c
Here, a=1, b=-6 c=5
The axis of symmetry is x=-b/2a
x= -(-6)/2(1)

x=6/2

x=3

Now the y term of the axis of symmetry just means you have to plug in x=3 in to your quadratic equation for find the y term of your vertex.

y=(3)²-6(3)+5

y=9-18+5

y=-9+5

y=-3

So the vertex is (-b/2a,f(-b/2a))

So it will be (3,-3)

300b(x) is graphed by the functio

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