Write the equation in slope-intercept form of a line that passes through the point (-6, -12) and is perpendicular to y=-2x+5.y=−2x+5.

Step-by-step explanation:

The standard form of equation of a line in slope-intercept form is expressed as:

y =mx+c

m is the slopw

c is intercept

Get the slope of the known line

since y = -2x+5

slope m = -2

Get the slope of unknown line

Since the unknown line is perpendicular to tis line, then

Mm = -1

M = -1/m

M = -1/-2

m = 1/2

Get the intercept of the unknown line:

Substitute the point (-6,12) and m = 1/2 into the equation y = mx+c

12 = 1/2(-6) + c

-12 = -3 + c

c = -12+3

c = -9

Get the equation of the unknown line:

Substitute m = 1/2 and c = -9 into the equation y = mx+c

y = 1/2x -9

2y = x - 18

2y-x = -18

Hence the equation in slope-intercept form of a line that passes through the point (-6, -12) and is perpendicular to y=-2x+5 is 2y-x = 18

multiple all that

step-by-step explanation:

27×17