Mathematics, 28.10.2020 19:30 bethdove9466

An archer is shooting at targets. The height of the arrow is 5 feet above the ground. Due to safety rules, the archer much aim the arrow parallel to the ground. How long does it take for the arrow to hit a target that is 3 feet above the ground? Round your answer to the nearest hundredth.

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Answer from: naenae2cold12021

The time to hit the target is simply the period the arrow gets to the target from the arch.

The time to hit the target is 0.35 seconds

The height of a parabola is calculated as:

$\mathbf{h = \frac{1}{2}gt^2}$

Where:

$\mathbf{h =5 - 3 = 2}$ --- the difference between the height of the arrow and the height of the target.

$\mathbf{g = 32.2 fts^{-2}}$ --- acceleration due to gravity

So, we have:

$\mathbf{2 = \frac{1}{2} \times 32.2 \times t^2}$

Multiply both sides by 2

$\mathbf{4 = 32.2 \times t^2}$

Divide both sides by 32.2

$\mathbf{0.124 = t^2}$

Take square roots

$\mathbf{0.35 = t}$

Rewrite as:

$\mathbf{t = 0.35s}$

Hence, the time to hit the target is 0.35 seconds

Read more about rates and time at:

link

Answer from: ace6112

The time it takes to hit a target that is 3 feet above ground is approximately 0.35 seconds

Step-by-step explanation:

The given parameters are;

The height of the arrow above the ground = 5 ft.

The height of the target above the ground = 3 ft.

The time it takes the arrow to fall to 3 ft. from 5 ft. above the ground is given by the free fall formula, since the arrow has no vertical velocity component

The equation for free fall is h = 1/2·g·t²

Where;

h = The height of fall = 5 - 3 = 2 feet

g = The acceleration due to gravity = 32.17405 ft/s²

t = How long it takes to fall (to its target)

∴ 2 = 1/2 × 32.17405 × t²

t² = 2/(1/2 × 32.17405) ≈ 0.1243

t = √0.1243 ≈ 0.353

t = 0.35 seconds, to the nearest hundredth

Therefore, the time it takes to fall 2 ft to hit a target that is 3 feet above ground = 0.35 seconds.

Answer from: Quest

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.

The graph below shows the value of a $100 deposited into three different accounts over a period of 2

Answer from: Quest

answer: yard ramps with a level off platform are typically 36 feet long. truck, rather than at an angle, enabling access to those pallets at the very back of the truck. if you are using your yard ramp to convert a loading dock into a drive-in door, we even at 60 inches (5 feet) high and a 30 foot ramp, the slope of the ramp will be less

step-by-step explanation: