Suppose an eagle is soaring at a height of 100 feet. If the eagle begins climbing at a rate of 7 feet per second, its height is given by the equation Y = 7x+100. In the
equation, x is the number of seconds and y is the eagle's height, in feet. Suppose the
eagle's original starting height had been 70 feet. What part of the graph of the linear
equation would change?

pls help!

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct

combine all like terms then its just a 2 step equation