Name that Ange pair! Drections Given the diagram below, determine whether the angle pairs are corresponding,
alternate interior, alternate exterior, consecutive (same-side) interior, consecutive (same-
side) exterior, or no relationship. Color the boxes using the color codes below.
3.
7
1
5
418
2
6
Corresponding Angles: Pink
Alternate Interior Angles: Light Blue
Alternate Exterior Angles: Yellow
Consecutive Interior Angles: Light Green
Consecutive Exterior Angles: Orange
No Relationship: Uncolored
9/13
10
14
1115
12
16

<2 and <13 are alternate interior angles

Reason: At the opposite sides of the transversal and fall between

<4 and < 11 are co-interior angles

Reason: Same side of the transversal and fall between the two parallel lines

<1 and <16 do not have any direct relationship

<3 and <12 are co-exterior angles

Reason: Same side of the transversal but each of them are outside the  parallel lines

<3 and <5 are co-interior angles

Reason: Same side of the transversal and fall between the two parallel lines

<14 and 16 are corresponding angles

Reason: They are at corresponding sides of the parallel lines to the transversal

<1 and <3 are corresponding angles

Reason: They are at corresponding sides of the parallel lines to the transversal

<5 and <10 are alternating exterior angles

Reason: Alternate side of the transversal but each of them are outside the  parallel lines

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∠6, ∠13, ∠2, ∠9, ∠4, ∠11, ∠8, ∠15 are corresponding angles

∠6, ∠9, ∠2, ∠13, ∠4, ∠15, ∠8, ∠11 are alternate interior angles

∠1, ∠14, ∠5, ∠10, ∠3, ∠16, ∠7, ∠12 are alternate exterior angles

∠6, ∠13, ∠2, ∠9, ∠4, ∠11, ∠8, ∠15 are consecutive interior angles

sry i dont  know which are the consecutive exterior angles

but i hope you understood

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!

it would be 6xy and -16xy.