Mathematics, 28.10.2020 18:20 1tzM3
An object is launched at 18.4 meters per second (m/s) from a 36.8-meter tall platform. The equation for the
object's heights at time t seconds after launch is s(t) = -4.9t^2+ 18.4t + 36.8, where s is in meters.
-When does the object strike the ground? | Select]
-How long did it take the object to get to its maximum height? Select]
-What was the height of the object at 3.32 seconds? Select]
Answers: 3
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An object is launched at 18.4 meters per second (m/s) from a 36.8-meter tall platform. The equation...
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