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Mathematics, 28.10.2020 17:50 jrfranckowiak

Line JK passes through points J(-3, 11) and K(1, -3). What is the equation of line JK in standard form? The answers are 7x + 2y = -1
7x + 2y = 1
14x + 4y = -1
14x + 4y = 1

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Line JK passes through points J(-3, 11) and K(1, -3). What is the equation of line JK in standard fo...

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