A 6-ft-tall person walks away from a 11-ft lamppost at a constant rate of 3.3 ft/sec. What is the rate that the tip of the person's shadow moves away from the lamppost when the person is 10 ft away from the lampost

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Complete Question

A 6-ft-tall person walks away from a 11-ft lamppost at a constant rate of 3.3 ft/sec. What is the rate that the tip of the person's shadow moves away from the lamppost when the person is 11 ft away from the lampost?

7.26ft/s

Step-by-step explanation:

A 6-ft-tall person walks away from a 11-ft lamppost at a constant rate of 3.3 ft/sec. What is the rate that the tip of the person's shadow moves away from the lamppost when the person is 11 ft away from the lampost?

Let x = distance of person to the tip of the lamp post

= 6/x = 11/d

Cross Multiply

6d = 11 x Equation 1

The constant rate of the person = 3.3 ft/s

= Distance of the person to the pole = Speed × time

= 3.3 × t

d = 3.3t

x = d - 3.3t

Substitute d - 3.3t for x in Equation 1

6d = 11x

6d = 11(d - 3.3t)

6d = 11d - 36.3t

36.3t = 11d - 6d

36.3t = 5d

d = 36.3/5

d = 7.26 ft/s

answer: 2530

hope this

step-by-step explanation: