wrtie an equation in slope-intercept form for the line that passes through the point (1,-1) and is parallel to the line whose equation is y= 2x+5

y = 2x - 3

Step-by-step explanation:

Since the line needs to be parallel, you can take the slope of the other equation and input it into y = mx + b:

y = 2x + b

Next, to have it intercept at the given coordinates, input the coordinates into the equation and solve for b:

-1 = 2 ( 1 ) + b

-1 = 2 + b

-1 - 2 = b

-3 = b

Now input the "b" value into the equation and you have the

y = 2x - 3

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form