Anyone can answer this? forth time of asking. Will give brainliest k * j = 1 (mod z) where k = 11, z = 24, find j

Step-by-step explanation:

k=11

z=24

substitute in the formula to find j

k×j=z

j=z/k

j=24/11

j= 2.1

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."