Tangela earns the same amount each week by babysitting. When she started this job, she had $200 in her savings account. The table shows Tangela's savings account balance for her first month of work. Week 0 1 2 3 4 Balance $200 $350 $500 $650 $800 Let x represent the number of weeks Tangela has been working and let y represent Tangela's account balance. Which equation, expressed in Slope-Intercept form, represents the amount of money in Tangela's bank account over time? y=150x+200

y=200x−150

y=150x−200

y=200x+150

y=150x+200

Step-by-step explanation:

Given that:

Week : 0___ 1 ___ 2 3 4

Balance : __200_350 _ 500 _ 650 ___800

Amount had in savings account = $200 before starting the job

x = number of weeks spent working

y = account balance

Slope intercept formula :

y = mx + c

C = intercept ; value of y when x = 0 = 200

m = slope or gradient = change in salary per month (350 - 200 = 500 - 350 = 650 - 500 = 800 - 650 = 150

Hence,

y = 150x + 200

a) y = -3x +2

b) y = 1/2x -6

these 2 can be combined into one equation.

-3x +2 = .5x -6

8 = 3.5x

x = 8 / 3.5 = 2.2857142857

y = -3 * (8 / 3.5) +2

y = (-24 / 3.5) + 2

y = -4.8571428571

step-by-step explanation: