line p has an equation of y=1/10x+6. perpendicular to line p is line q, which passes through the point (1,-9). what is the equation it q?

y = - 10x + 1

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = x + 6 ← is in slope- intercept form

with slope m =

Given a line with slope m then the slope of a line perpendicular to it is

= - = - = - 10, thus

y = - 10x + c ← is the partial equation

To find c substitute (1, - 9 ) into the partial equation

- 9 = - 10 + c ⇒ c = - 9 + 10 = 1

y = - 10x + 1 ← equation of line q

left 3, up 4

step-by-step explanation:

just count the values of x & y of the vertex of the graph and see how many units in the x and y direction will get you from the f(x) graph to the f(x) graph

use this formula:

p(a\b) = p(a and b)/p(b).

take it from here.