Work out the first four terms and the 10th term of the quadratic sequence with
a T(n) = 2n2 + 4
b T(n) = 3n2-3
c T(n) = -3n2 + 7
d T(n) = 4n? -5

a. The first four terms and the 10th term are 6, 12, 22, 36, , 204

b. The first four terms and the 10th term are 0, 9, 24, 45, , 297

c. The first four terms and the 10th term are 4, -5, -20, -41, , -293

d. The first four terms and the 10th term are -1, 11, 31, 59, , 395

Step-by-step explanation:

a.

∵ T(n) = 2n² + 4 is the rule of the sequence, where

∴ For the first term, n = 1

→ Substitute n by 1 in the rule above to find T(1)

∵ T(1) = 2(1)² + 4 = 2(1) + 4 = 2 + 4

∴ T(1) = 6

→ For the second term, n = 2

∵ T(2) = 2(2)² + 4 = 2(4) + 4 = 8 + 4

∴ T(2) = 12

→ For the third term, n = 3

∵ T(3) = 2(3)² + 4 = 2(9) + 4 = 18 + 4

∴ T(3) = 22

→ For the fourth term, n = 4

∵ T(4) = 2(4)² + 4 = 2(16) + 4 = 32 + 4

∴ T(4) = 36

→ For the tenth term, n = 10

∵ T(10) = 2(10)² + 4 = 2(100) + 4 = 200 + 4

∴ T(10) = 204

The first four terms and the 10th term are 6, 12, 22, 36, , 204

b.

∵ T(n) = 3n² - 3 is the rule of the sequence

→ For the first term, n = 1

∵ T(1) = 3(1)² - 3 = 3(1) - 3 = 3 - 3

∴ T(1) = 0

→ For the second term, n = 2

∵ T(2) = 3(2)² - 3 = 3(4) - 3 = 12 - 3

∴ T(2) = 9

→ For the third term, n = 3

∵ T(3) = 3(3)² - 3 = 3(9) - 3 = 27 - 3

∴ T(3) = 24

→ For the fourth term, n = 4

∵ T(4) = 3(4)² - 3 = 3(16) - 3 = 48 - 3

∴ T(4) = 45

→ For the tenth term, n = 10

∵ T(10) = 3(10)² - 3 = 3(100) - 3 = 300 - 3

∴ T(10) = 297

The first four terms and the 10th term are 0, 9, 24, 45, , 297

c.

∵ T(n) = -3n² + 7 is the rule of the sequence

→ For the first term, n = 1

∵ T(1) = -3(1)² + 7 = -3(1) + 7 = -3 + 7

∴ T(1) = 4

→ For the second term, n = 2

∵ T(2) = -3(2)² + 7 = -3(4) + 7 = -12 + 7

∴ T(2) = -5

→ For the third term, n = 3

∵ T(3) = -3(3)² + 7 = -3(9) + 7 = -27 + 7

∴ T(3) = -20

→ For the fourth term, n = 4

∵ T(4) = -3(4)² +7 = -3(16) + 7 = -48 + 7

∴ T(4) = -41

→ For the tenth term, n = 10

∵ T(10) = -3(10)² + 7 = -3(100) + 7 = -300 + 7

∴ T(10) = -293

The first four terms and the 10th term are 4, -5, -20, -41, , -293

d.

∵ T(n) = 4n² - 5 is the rule of the sequence

→ For the first term, n = 1

∵ T(1) = 4(1)² - 5 = 4(1) - 5 = 4 - 5

∴ T(1) = -1

→ For the second term, n = 2

∵ T(2) = 4(2)² - 5 = 4(4) - 5 = 16 - 5

∴ T(2) = 11

→ For the third term, n = 3

∵ T(3) = 4(3)² - 5 = 4(9) - 5 = 36 - 5

∴ T(3) = 31

→ For the fourth term, n = 4

∵ T(4) = 4(4)² - 5 = 4(16) - 5 = 64 - 5

∴ T(4) = 59

→ For the tenth term, n = 10

∵ T(10) = 4(10)² - 5 = 4(100) - 5 = 400 - 5

∴ T(10) = 395

The first four terms and the 10th term are -1, 11, 31, 59, , 395

let's solve your equation step-by-step.

4x+2=2x+12

step 1: subtract 2x from both sides.

4x+2−2x=2x+12−2x

2x+2=12

step 2: subtract 2 from both sides.

2x+2−2=12−2

2x=10

step 3: divide both sides by 2.

2x

2

=

10

2

x=5

step-by-step explanation:

c.

step-by-step explanation:

because first you have to add the 4x, 9x, and the 7x together and you get 20x and then you add the last numbers up and you get 5and then you put the subtraction sign in there and that's how you get the answer.