Can someone help me with this??

y= -2x-2

Step-by-step explanation:

All parallel lines have the same slope. So, the line we create must have a slope of -2. If we multiply the x value by -2, we can find b through an equation.

-4 would be x in this case because it's a point we pass.

So, our equation would be

y= -2(-4)+b

y=8+b

Now, we know that y is 8+b. We can find b by plugging in y=6, because those are the coordinates of P.

6=8+b

b=-2

Now we know that b is -2. We put this into the equation for the parallel line and get:

y=-2x-2

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)