Given f(x)=x^2-4x+4 find the value(s) for x such that f(x)=25

To solve this, first factor f(x)

F(x) = (x-2)^2 = 25

Next, take the root of each side:

(x - 2) = +/- 5

So now we are left with two functions:

x - 2 = 5
x - 2 = -5

These yield the results
x = -3 & x = 7

So, for x = -3 & x= 7, f(x) will equal 25.