Seat belt use in a state was estimated at %, which means % of people use their seat belts. Suppose two independent drivers have been randomly selected. a. What is the probability that both of them are using a seatbelt? b. What is the probability that neither of them is using a seatbelt? c. What is the probability that at least one is using a seatbelt? a. The probability that both of them are using a seatbelt is 0.3. (Type an integer or a decimal. Do not round.)

Question

Seat belt use in a state was estimated at 89%,

which means 89 % of people use their seat belts. Suppose two independent drivers have been randomly selected.

a. What is the probability that both of them are using aseatbelt?

b. What is the probability that neither of them is using aseatbelt?

c. What is the probability that at least one is using aseatbelt?

The probability that both of them are using a seatbelt is ?

a

b

c

Step-by-step explanation:

From the question we are told that

    The proportion of seat belt use is  p =  0.89

     The  sample  size n =  2

Generally the probability that both drivers are wearing seat belt is mathematically represented as

=>    

=>    

Generally the probability that neither of the two drivers are wearing seat belt is  

=>  

=>  

Generally the probability that at least one of the drivers is wearing a seat belt is  

=>    

=>    

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)