X^2/y^3 * x/y^4. How do you solve that?

Gradient = rise/run

Say you are given two points (a,b) and (c,d)

Gradient = (d-b)/(c-a)

In the case of your question,

Gradient

= [(-3) - (-1)] ÷ [(-4) - (-2)]

= -2 ÷ -2

= 1

From there, you can sub the gradient and one of the points into the gradient-intercept form of a line to get:

y - (-1) = 1(x - (-2))

y + 1 = x + 2

y = x + 1

hope it help :)

Step-by-step explanation:

step-by-step explanation:

where is the questions

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.