Molly is looking up at the the St. Louis Arch, which stands 630 feet high. The angle of elevation, q, from her line of sight to the top of the monument depends on the distance, d, she is from the base. If Molly's eyes are 5 feet 3 inches from the ground, write a function for q in terms of d.

this is tricky b/c of Sin() , Cos() and Tan() functions  remember the Mnemonic SOH CAH TOA   to help remember how those functions work

Step-by-step explanation:

so they asked for a function  d(q)   or    d= q  okay?

so what is that relationship of d & q    since I wrote down the SOH CAH TOA reminder which of those might help us for this  Sin()= Opp/ Hyp   or  Cos()=Adj/Hpy or Tan()=Opp / Adj    So Molly will be standing where we are going to find the angle q, so  from there, that point... the Adj side is d .. huh.. and the Opposite side is going to be the 630 foot tall Arch of that imaginary triangle from Molly to the base of the Arch and from Molly to the top of the Arch.. s lets use Tan() since that one seems to have the parts of info that we are given in this question.  

Tan()=Opp / Adj    where Tan(Ф)  is q and that opposite side is the 630 minus Molly's 5'-3"height     and d is the adjacent side so the formula now looks like this

q = (630- 5'3") / d    if we then move those around and say that

d = (630-5'3") / q then we've got the equation in a pretty easy to see form.    

We can also put in Tan() if we want so that the formula can be solved once you know the angle Molly is looking up at.    so then the formula looks like  d= (630-5'3")/ Tan(Ф)    

if that makes sense?   :)

where is the gragh

step-by-step explanation:

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