Mathematics, 26.10.2020 22:40 softball2895

Y 8
What is the pre-image of vertex A if the rule that created
the image is Ty-axis(x, y) - (-x, y)?
O A(-4,2)
O A(-2,-4)
O A(2,4)
O A(4,-2)
4
A
x
8
4
8
4
-8
C'
B'

Y

8
What is the pre-image of vertex A if the rule that created
the image is Ty-axis(x, y) - (-x,y

Answers: 3

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Answers

Answer from: Quest

he used the algebra tiles correctly.

step-by-step explanation:

given : 3x(2x-1)

solution :

since he used algebra tiles .

armando's solution is the same in the solution shown in figure

as he distributed 2x into x and x and wrote them vertically

and also write -1 vertically

and 3x into x and x and x and wrote it horizontally

performing the multiplication in the algebra tiles we get $6x^{2} -3x$

and solving the given expression :

3x(2x-1)

$6x^{2} -3x$

since solving the expression using tiles and solving the expression algebraically we get the same answer

thus we can choose the first statement as the answer to this problem which is "he used the algebra tiles correctly".

Which is true regarding armando’s use of algebra tiles? he used the algebra tiles correctly. he did

Answer from: Quest

6,250

step-by-step explanation:

to get the area, multiply 360 by 160.(57,600)

to find out how many bags of fertilizer it will take, first figure out how many square feet one bag can hold. divide 1000 by 8(125) to get the unit rate(how many square feet one pound of fertilizer can hold)and multiply it by 50(6250). if i haven't made a mistake, that is the answer.

Answer from: Quest

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

$x^2-2x+y^2-6y=26$

we now create space between the x and y terms with parenthesis.

$(x^2-2x)+(y^2-6y)=26$

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

$\frac{-2}{2} =(-1)^{2} =1$

$\frac{-6}{2} =(-3)^{2} =9$

we add the squares to both sides.

$(x^2-2x+1)+(y^2-6y+9)=26+1+9$

simplify.

$(x^2-2x+1)+(y^2-6y+9)=36$

and write the quadratics in factored form.

$(x-1)^{2} +(y-3)^{2} =36$

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.

Answer from: Quest

aloha~! my name is zalgo and i am here to you out on this amazing day. to answer your question, yes, nonzero numbers can have a greatest common factor and that would be 1. still don't get it? let me considering every number is divisible by 1 and hence every number has 1 as a factor of theirs. so, if 2 nonzero numbers didn't share any gcf (greatest common factor), they would still have a factor in common and that would be 1.

i hope that this ! : p

"stay and stay proud! " - zalgo

(by the way, do you mind marking me as brainliest? i'd greatly appreciate it! mahalo! x3)