Function K(v) represents the kinetic energy, in joules, of an object with a mass of 20 kilograms traveling with velocity v meters/second (m/s). The difference quotient of K(V) is 20V + 10h. What is the average rate of change in
kinetic energy of an object as the velocity increases from 5 m/s to 12.5 m/s?
175 joules per m/s
225 joules per m/s
300 joules per m/s
325 joules per m/s

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)

b) k’(6, 4); l’(3, 3)

step-by-step explanation:

a 270° clockwise rotation maps every point (x, y) to (y, -x). (it negates the x-coordinate and then switches it and the y-coordinate.)

this means the endpoints of the side congruent to kl, k' and l', would be mapped as:

k'(-4, 6)→(6, 4)

l'(-3, 3)→(3, 3)

but there’s no any figure there!